Question

Calculate total number of atoms (In terms of NA) present in 34 g of NH3. Where NA is Avogadro's number.

Answer 1

Answer:

Given Mass of NH₃= 34g

Molar Mass of NH₃= 17g

∴ No. of moles of NH₃=Given Mass÷Molar Mass=34÷17= 2 Moles

∴ Total number of atoms (In terms of NA) present in 34 g of NH₃= No. of moles of NH₃ × NA = 2×6.022×10²³= 12.044 ×10²³ atoms of NH₃

∴ There are 12.044 ×10²³ atoms present in 34 g of NH₃

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