Calculate value of acceleration due to gravity inside earth depth equal to half the radius?
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g = Gm/r²
If we take r = r/2
Then,
g = Gm/(r/2)
g = Gm/ r²/4
gr² = 4Gm -----------(1)
put Gm = gr²/4
g = gr²/4 / r²
gr² = gr²/4
g = g/4
g = 4g
g = 10 ×4
g = 40m/s²
And g is inversely proportional to r²
when radius of earth decreases then the value of g increases
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