Question

Calculate volume of CO2 at STP obtained by treating 10 g of pure marble with dilute HCI​

Answer 1

Explanation:

ANSWER

CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

100g or one mole 24000ml

100 g of CaCO

3

gives 22400 ml of carbon dioxide.

10 g of CaCO

3

gives =

100

22400

×10=2240 ml of carbon dioxide.

If the metal is 100% pure, 2240 ml of carbon dioxide is produced.

1120 ml of carbon dioxide is produced in this case.

So the % purity =

2240

100

×1120=50%