Question

Calculated the escap velocity of a body from the surface of the earth

Answer 1

${GMm}{ x^{-2} } } \, dx$Escape velocity is defined as the minimum velocity with which a body has to be projected vertically upwards from the surface of the earth so that it just crosses the gravitational field of the earth and never returns on its own.
 
F =$\frac{GMm}{ x^{2} }$ 

dW= F dx =$\frac{GMm}{ x^{2} }$ dx

W= $\int\limits^[tex] \int\limits^∞_R { x^{-2} } \, dx$_R {$\frac W= {GMm}{ x^{2} }$ } \, dx [/tex]

Check attachment 

Answer 2

Answer:

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