Calulate the ph of 10 power-8 M HCL solution?
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it's pH is 1........
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pH=−log([H3O+])
========== therefore =============
HCl(aq]+H2O(l]→H3O+(aq]+Cl−(aq]
==================
pH=−log(1.051⋅10−7)=6.98
========== therefore =============
HCl(aq]+H2O(l]→H3O+(aq]+Cl−(aq]
==================
After the acid has been added, water's self-ionization produces xmoles of hydronium ions and x moles of hydroxide ions. You can say that
(x+10−8)⋅x=10−14
thereforepH=−log(1.051⋅10−7)=6.98
arsenicnabeelk:
Dudee logically it is hcl not the water in ur loo how come it be so high jkjkjk
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