Can any one answer Q.no.24
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Answered by
3
2BD=BC
In right ΔABD
AB²=BD²+AD²
BC²=BD²+AD²
(2BD)²=BD²+AD²
4BD²=BD²+AD²
⇒AD²=3BD²
Cheers and mark as brainliest!!
In right ΔABD
AB²=BD²+AD²
BC²=BD²+AD²
(2BD)²=BD²+AD²
4BD²=BD²+AD²
⇒AD²=3BD²
Cheers and mark as brainliest!!
Answered by
4
Here's ur answer....
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raajkumar:
hii
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