Math, asked by BiswajitBiswas, 1 year ago

find the value of this

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Answered by yashika41

1

=(secQ×secQ)-( tanQ×tanQ)+1/tan10.tan20.root3.cot20.cot10
=(sec^2Q-tan^2Q)+1/ tan10. tan20. 1/tan20×1/tan10×root3
=1+1/root3
2/root3
2root3/3

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