can anyone help me with this
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In order to prove that AB and CD
bisect each other at 0, it is sufficient
to prove that
∆AOD =~ ∆BOC
In these two triangles,
we have
AD = BC
∆OBC = ∆OAD {AD = BC and AB is
transversal }
so, by As A congruence criterion , we obtain
∆AOD =~ ∆BOC
= OA =OB and OD =OC=
AB and CD bisect each other at o.
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