Math, asked by pt8151527, 7 months ago

Five years hence, rhe age of nuri will be three times that of sonu. five years ago,Nuri's age was seven times that of sonu. what are their present age.​

Answers

Answered by Anonymous
24

Answer:

Present age of Nuri is 40 years and present age of Sonu is 10 years.

Step-by-step explanation:

Given :-

  • 5 years hence, the age of Nuri will be three times that of Sonu.
  • 5 years ago, Nuri's age was 7 times that of Sonu.

To find :-

  • Their present ages.

Solution :-

Consider,

  • Present age of Nuri = x years
  • Present age of Sonu = y years

5 years hence,

  • Nuri's age = (x+5) years
  • Sonu's age = (y+5) years

According to the 1st condition,

(x+5) = 3(y+5)

→ x+5 = 3y + 15

→ x = 3y + 15-5

→ x = 3y +10..................(i)

5 years ago,

  • Age of Nuri = (x-5) years
  • Age of Sonu = (y-5) years

According to the 2nd condition,

(x-5) = 7(y-5)

→ x-5 = 7y - 35

→ 3y+10-5 = 7y-35 [put x = 3y+10 from eq(i)]

→ 3y - 7y = -35 - 10 +5

→ -4y = -40

→ y = 10

Therefore,

★ Present age of Sonu = 10 years

Now put y = 10 in eq(i)

x = 3y+10

→ x = 3× 10 + 10

→ x = 40

★ Present age of Nuri 40 years.

Answered by ranjita2211
12

Answer:

nuri's present age is 40 and sonu's present age is 10

Step-by-step explanation:

let nuri's age be x and sonu's age be y

a/q,

x+5=3(y+5)

x+5=3y+15

x-3y=10

x=3y+10----(1)

in the question it's also given that,

x-5=7(y-5)

x-5=7y-35

x-7y=-30-----(2)

putting (1) in (2)

10+3y-7y=-30

-4y=-40

y=10

x=10+3(10)

x=40

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