Can anyone one solve the 9th question
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Let the ratio in which P(x,y) divide AB be k:1
x=a+0/k+1
y=0+bk/k+1
L.H.S x/a+y/b= a/k+1/a + bk/k+1/b
= a/a(k+1) + bk/b(k+1)
= 1/k+1 + k/k+1
= 1+k/k+1 = 1
Hence , Proved...
Thank You !
x=a+0/k+1
y=0+bk/k+1
L.H.S x/a+y/b= a/k+1/a + bk/k+1/b
= a/a(k+1) + bk/b(k+1)
= 1/k+1 + k/k+1
= 1+k/k+1 = 1
Hence , Proved...
Thank You !
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