Question

can anyone please answer this question ​

Answer 1

Step-by-step explanation:

i did not the answer sorry

Answer 2

Answer:

FIRST OF ALL,,, I sathvi.. i like u very much,, take my instagram from my profile,,, plz and i want to talk you...

Step-by-step explanation:

And here is your answer,,

Given:-

QMperpendicularPR

PR²-PQ²=QR²

TO PROVE :-

QM²=PM×MR

PROOF:-

PR²-PQ²=QR²

PR²=QR²+PQ²

Therefore,

By converse of PGT,

angle Q = 90°

Now,

In,ΔQMR,

angleR= 90°- angleMQR (1)

InΔPQR,

angleR= 90°- angleP (2)

From eq(1) &Eq(2)

90 - angleMQR = 90° - angleP

angle MQR = angle P

In ΔPMQ & ΔQMR,

QMP = QMR (90°)

MQR = QPR (proved above)

ΔPMQ similar ΔQMR ( AA Simirality )

QM PM

RM = QM

QM²= PM × RM

Sathvi ..plz ..

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