can anyone plz answer this??????
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smartcow1:
I'm sorry but I do not know
its ok
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Answered by
0
The correct answer is option B - 3N
We can calculate the tension by using the formula - Fnet = Fa - Ffr = ma
a = (Fa - Ffr)/m
So, total m = 1 + 2 = 3 kg
Fa = 0.1 N
Ffr = μFn = μmg
= 0.1 x 3 x 9.8
So, a = [12 N - (0.1 x 3 x 9.8)]/3
a = 3.02 m/s²
We can calculate the tension by using the formula - Fnet = Fa - Ffr = ma
a = (Fa - Ffr)/m
So, total m = 1 + 2 = 3 kg
Fa = 0.1 N
Ffr = μFn = μmg
= 0.1 x 3 x 9.8
So, a = [12 N - (0.1 x 3 x 9.8)]/3
a = 3.02 m/s²
Answered by
2
Answer:
3.02 m/s²
Explanation:
The correct answer is option B - 3N
We can calculate the tension by using the formula - Fnet = Fa - Ffr = ma
a = (Fa - Ffr)/m
So, total m = 1 + 2 = 3 kg
Fa = 0.1 N
Ffr = μFn = μmg
= 0.1 x 3 x 9.8
So, a = [12 N - (0.1 x 3 x 9.8)]/3
a = 3.02 m/s²
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