can anyone solve please
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Heya,
In triangle ABC, angle C = 90deg.
To find the diagonal:-
AC^2 = AB^2 + BC^2
AC^2 =9^2 + 40^2
AC^2 = 81 + 1600
AC^2 = √1681
For rest of the solution plz check the attachment above. :)
Regards,
Shobana
In triangle ABC, angle C = 90deg.
To find the diagonal:-
AC^2 = AB^2 + BC^2
AC^2 =9^2 + 40^2
AC^2 = 81 + 1600
AC^2 = √1681
For rest of the solution plz check the attachment above. :)
Regards,
Shobana
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