Two pipes running together can fill a cistern in 2 8/11
minutes. If one pipe takes 1 minute more than the other to fill the cistern, find the time in which each pipe would fill the cistern alone
Answers
Answer:
Pipe 1 fill the cistern alone in 5 minutes and Pipe 2 fill the cistern alone in 6 minutes
Step-by-step explanation:
Let Pipe 1 fill the cistern alone in x minutes
We are given that one pipe takes 1 minute more than the other to fill the cistern
SO, Pipe 2 fill the cistern in x+1 minutes
Pipe 1's 1 minute work =
Pipe 2's 1 minute work =
They work together in 1 minute =
We are also given that Two pipes running together can fill a cistern in 2 8/11 i.e. 30/11
So, their together 1 minute work =
So,
S, since minutes cannot be negative
So, x = 5
So, Pipe 1 fill the cistern alone in 5 minutes and Pipe 2 fill the cistern alone in x+1 = 5+1 = 6 minutes
Hence Pipe 1 fill the cistern alone in 5 minutes and Pipe 2 fill the cistern alone in 6 minutes