the product of four consecutive positive integers is 840 find the numbers?
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Let the 4 consecutive numbers be= x,x+1,x+2,x+3
Solution:
X+(x+1)+(x+2)+(X+3) =840
4x+6=840
4x=840-6
X=834\4
X= 208.5
So,
The four consecutive numbers are 208.5,209.5,300.5,301.5
Solution:
X+(x+1)+(x+2)+(X+3) =840
4x+6=840
4x=840-6
X=834\4
X= 208.5
So,
The four consecutive numbers are 208.5,209.5,300.5,301.5
priya479:
thanx
Ye ans wrong h yr
or mera correct ans ko delete kr diye
wah yr ye ky....... h
U r and is wrong I
Bhai ap sum kiye ho
but que me product bola h
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