Question

a bike riding at 22.4m/s skids to come to a halt in 2.55s.Conclude the skidding distance of the bike.

Answer 1

Given:-

Initial speed i.e  u= 22.4 m/s

Final speed  i.e.  v=0 m/s

Time taken to come to stopping position  t= 2.55 sec

We wish to determine an acceleration (retardation) a=?

We have equation of the motion   v=u+at

0=22.4+2.55×a

-2.55a=22.4

a=22.4/(-2.55)

=-8.784 ms^(-2)

v² =u² +2as

0=(22.4)^2+2×s×(-8.784)

-501.76=-17.568s

s=28.56 m

Distance of the bike 28.56 m.