can anyone solve this ?
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Answer:
{(27)^2n/3×(8)^-n/6}/(18)^-n/2
={(3)^2n×3/3×(2)^-n×3/6}/(9×2)^-n/2
={3^2n×2^-n/2}/9^-n/2×2^-n/2
=(3^2n×2^-n/2)/3^-n×2/2×2^-n/2
=(3^2n×2^-n/2)/(3^-n×2^-n/2)
=3^(2n+n)
=3^3n
=27^n
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