Math, asked by prasadlakhmi5, 1 month ago

can anyone solve this ?

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Answers

Answered by bagkakali
1

Answer:

{(27)^2n/3×(8)^-n/6}/(18)^-n/2

={(3)^2n×3/3×(2)^-n×3/6}/(9×2)^-n/2

={3^2n×2^-n/2}/9^-n/2×2^-n/2

=(3^2n×2^-n/2)/3^-n×2/2×2^-n/2

=(3^2n×2^-n/2)/(3^-n×2^-n/2)

=3^(2n+n)

=3^3n

=27^n

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