Question

can anyone solve this
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Answer 1

In the given figure, we have a rectangle of length 50 cm and width 10 cm and two similar

trapeziums with parallel sides as 30 cm and 10 cm at both ends.

Suppose x is the perpendicular distance between the parallel sides in both the trapeziums.

We have:

Total length of the given figure = Length of the rectangle + 2 × Perpendicular distance between the parallel sides in both the trapeziums

70 = 50 + 2 × x

2 × x = 70 – 50 = 20

x =202 m = 10 cm.

Now, area of the complete figure = (area of the rectangle with sides 50 cm and 10 cm) + 2 × (area of the trapezium with parallel sides 30 cm and 10 cm, and height 10 cm)

= (50 × 10) + 2 × [ 1/2 × (30 + 10) × (10)] = 500 + 2 × [200] = 900 cm2.

Hope it help