Question

Can anyone tell me answer of this question ....
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Answer 1

☆Hey Shanaya!!!!☆


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Here is your answer ☞
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● N2(g) + 3H2(g) ===> 2NH3(g)

Now,

● N2 => 14×2 = 28gm

● 3H2 => 3×2 = 6gm

● 2NH3 => 2×17 = 34gm

Then,


● 28gm of N2 react with 6g of H2 to form 34g of NH3

and

● 50gm of N2 will react with = (6/28)×50

= 10.71gm of H2

● Available amount of H2. = 10gm

Therefore, H2 is the limiting reagent


Now,

● 6gm H2 gives 34gm NH3

So,

● 10gm H2 will give = (34/6)×10

= 56.67gm NH3 ______answer


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hope it will help you ☺☺☺
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Devil_king ▄︻̷̿┻̿═━一

Answer 2

Explanation:

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