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RaunakRaj:
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Answered by
1
Let one integer be x
Then, second integer=x+1
ATQ,
x+x+1=45
2x=45-1
2x=44
x=44÷2
x=22
Thus,
one integer=x=22
second integer=x+1=22+1=23
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Then, second integer=x+1
ATQ,
x+x+1=45
2x=45-1
2x=44
x=44÷2
x=22
Thus,
one integer=x=22
second integer=x+1=22+1=23
HOPE IT WILL HELP U...
PLZ MARK IT AS BRAINLIEST ANSWER
Answered by
1
hello friend!!
the solution is:))
LET the 1st no. be => x
therefore we can say that according to question :
the other conscutive integer will be => x+1
therefore,
now,
according to question:-
the sum of two consecutive integer is: 45
therefore:-
=>x+x+1=45
=>2x+1=45
=>2x=45-1
=>2x=44
=>x=44/2
=>x=22
therefore x=22-------1st no.
so second no.=x+1
22+1
=>23
so 1st no.=21 and second no.=23.---->answer
hope this helps you !!
please mark my answer as brainliest!!
thank you!!:))))
the solution is:))
LET the 1st no. be => x
therefore we can say that according to question :
the other conscutive integer will be => x+1
therefore,
now,
according to question:-
the sum of two consecutive integer is: 45
therefore:-
=>x+x+1=45
=>2x+1=45
=>2x=45-1
=>2x=44
=>x=44/2
=>x=22
therefore x=22-------1st no.
so second no.=x+1
22+1
=>23
so 1st no.=21 and second no.=23.---->answer
hope this helps you !!
please mark my answer as brainliest!!
thank you!!:))))
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