Can somebody plz help for this question of class 9th.
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I)it's a triangle,so ar of Δ=1/2*b*h=(1/2*1*5)cm=2.5cm²
II)It's a rectangle,so ar of rect.=l*b=(6.5*1)cm=6.5cm²
III)It's a trapezium,so ar of trap.=1/2(a+b)*h={1/2(1+2)*1}cm=3/2cm²=1.5cm²
IV)It's a ri8 angled Δ,therefore,ar of Δ=1/2*b*a=1/2*6*1.5=4.5cm²
V)its again a Δ of same sides so,ar of Δ=4.5cm²
adding all the above value u'll get the total area of the paper used
so,[2.5+6.5+1.5+(4.5*2)]cm²=19.5cm²
thus,19.5 is the required area of the total paper used.
II)It's a rectangle,so ar of rect.=l*b=(6.5*1)cm=6.5cm²
III)It's a trapezium,so ar of trap.=1/2(a+b)*h={1/2(1+2)*1}cm=3/2cm²=1.5cm²
IV)It's a ri8 angled Δ,therefore,ar of Δ=1/2*b*a=1/2*6*1.5=4.5cm²
V)its again a Δ of same sides so,ar of Δ=4.5cm²
adding all the above value u'll get the total area of the paper used
so,[2.5+6.5+1.5+(4.5*2)]cm²=19.5cm²
thus,19.5 is the required area of the total paper used.
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