Question

Can someone answer the 22nd one properly please with steps

Answer 1

We know that , if m is the midpoint fo a class and h is the class size,

then lower limit of class interval =m−

2

h

Upper limit of class interval =m+

2

h

We have class sixe, 15−5=10

so the class interval formed from the midpoint 5 is

=(5−

2

10

)−(5+

2

10

)i.e0−10

Containing in the same manner, the continuous classes formed are;

{class intervals} 6-10| 10-20|30-40|40-50

{Frequency} 4 |8 |13 |12 |6