Question

Can someone help me​

Answer 1

Answer:

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Step-by-step explanation:

In quadrilateral ABCD, ∠A + ∠B + ∠C + ∠D = 360 °.

From above, ∠A + ∠B = 360 ° - ∠C - ∠D is gotten.

In ΔOAB, $\frac{1}{2}$( ∠A + ∠B ) + ∠AOB = 180 °.

$\frac{1}{2}$( ∠A + ∠B ) = 180 ° - ∠AOB

From above, ∠A + ∠B = 360 ° - 2∠AOB is gotten.

Two expressions can be combined to make :

360 ° - 2∠AOB = 360 ° - ∠C - ∠D.

2∠AOB = ∠C + ∠D

∴∠AOB = $\frac{1}{2}$( ∠C + ∠D )

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