Question

can someone solve this ​

Answer 1

Answer:

Send the full head line please..........

Answer 2

Answer:

838$cm^{2}$

Step-by-step explanation:

First you have to find the area of ABCF

  Area of ABCF = $\frac{a+b}{2} h$   (area of trapezium)

                          =$\frac{28+16}{2}25$ $cm^{2}$

                          =$\frac{44}{2}25$$cm^{2}$

                          =22 x 25$cm^{2}$

                          =550$cm^{2}$

Now, area of FCED = L x B

                                = 16 x 18$cm^{2}$

                                = 288$cm^{2}$

So, area of ABCDEF = Area of ABCF + area of FCED

                                  = 550 + 288$cm^{2}$

                                  = 838$cm^{2}$

Hope it helps you...

THANKS<3