Question

3.
A spherical concave showing Mirror has a radius of
curvature of 25 cm. What is the magnification produced
when the face is 10 cm from the pole of the mirror?
- Sol​

Answer 1

Answer:

Radius of curvature=35cm

Focal length=

2

35

cm

Given ,

heightofobject

heightofimage

=

u

−v

=2.5

−v=2.5u⇒v=

10

−25

u

For a mirror,

v

1

+

u

1

=

f

1

⇒

−25u

10

+

u

1

=

35

2

⇒

u

1

(1−

25

10

)=

35

2

⇒u=

25

25−10

×

2

35

=u

u=

25×2

15×35

=

2

21

cm

u=10.5cm

pls follow me

Answer 2

Explanation:

Radius of curvature=35cm

Focal length=

2

35

cm

Given ,

heightofobject

heightofimage

=

u

−v

=2.5

−v=2.5u⇒v=

10

−25

u

For a mirror,

v

1

+

u

1

=

f

1

⇒

−25u

10

+

u

1

=

35

2

⇒

u

1

(1−

25

10

)=

35

2

⇒u=

25

25−10

×

2

35

=u

u=

25×2

15×35

=

2

21

cm

u=10.5cm