Question

can the no. 6^n, n being a natural no.,end with the digit 5?give reason with proper calculation

Answer 1

No, 6^n can never end with the digit 5.

Lets take an example
6^1= 6
6^2= 36
6^3= 216
6^4= 1296
6^5= 7776
And so on

Thus it could be also said that 6^n will end only with the digit 6 no matter what the value of "n" be (until n is a natural number)