can the no. 6^n, n being a natural no.,end with the digit 5?give reason with proper calculation
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No, 6^n can never end with the digit 5.
Lets take an example
6^1= 6
6^2= 36
6^3= 216
6^4= 1296
6^5= 7776
And so on
Thus it could be also said that 6^n will end only with the digit 6 no matter what the value of "n" be (until n is a natural number)
Lets take an example
6^1= 6
6^2= 36
6^3= 216
6^4= 1296
6^5= 7776
And so on
Thus it could be also said that 6^n will end only with the digit 6 no matter what the value of "n" be (until n is a natural number)
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