can u please answer this question plzz
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perimeter= 2(l+b)
length= 2b
2(2b+b) = 177
6b=177
b= 29.5 ft
l =59 ft
length= 2b
2(2b+b) = 177
6b=177
b= 29.5 ft
l =59 ft
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shape of the volleyball ground is of rectangle
so perimeter of rectangle is = 2(L+B)
where L=length n B = breadth or width of rectangle
so given that 2(L+B) = 177ft ............1
n L =2 B
putting the value of L in 1 v get
2(2B+B) =177ft
6B = 177 B= 177/6 = 29.5ft
and L=2*29.5= 59ft
therefore L=59ft n B=29.5ft
so perimeter of rectangle is = 2(L+B)
where L=length n B = breadth or width of rectangle
so given that 2(L+B) = 177ft ............1
n L =2 B
putting the value of L in 1 v get
2(2B+B) =177ft
6B = 177 B= 177/6 = 29.5ft
and L=2*29.5= 59ft
therefore L=59ft n B=29.5ft
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