can u prove that underoot 5 is irrational
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Hey dear!
Here is yr answer......
Let us assume √5 is rational
let √5 = a/b ( a, b are co-primes)
=> b√5 = a
Squaring on both sides....
=> 5b² = a²
=> a² = 5b²
Here, 5 divides a²
therefore, 5 also divides a ----------(1)
let, a = 5c
by sub. a = 5c in a² = 5b²
=> (5c)² = 5b²
=> 25c² = 5b²
=> 5c² = b²
=> b² = 5c²
Since, 5 divides b²
Therefore, 5 also divides b ------------(2)
From (1) & (2),
we conclude that, a and b are not co-primes!
So, our assumption is false
Therefore, √5 is irrational!
Hope it hlpz...
Here is yr answer......
Let us assume √5 is rational
let √5 = a/b ( a, b are co-primes)
=> b√5 = a
Squaring on both sides....
=> 5b² = a²
=> a² = 5b²
Here, 5 divides a²
therefore, 5 also divides a ----------(1)
let, a = 5c
by sub. a = 5c in a² = 5b²
=> (5c)² = 5b²
=> 25c² = 5b²
=> 5c² = b²
=> b² = 5c²
Since, 5 divides b²
Therefore, 5 also divides b ------------(2)
From (1) & (2),
we conclude that, a and b are not co-primes!
So, our assumption is false
Therefore, √5 is irrational!
Hope it hlpz...
varunbhardwaj:
thanks dear
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