Question

Can we construct a rectaugle with perimetev 14cm are area 25cm2? Ans​

Answer 1

Answer:

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Answer 2

Answer:

Yes, we can create a rectangle with area  25cm^2 and perimeter 14cm.

2(l+b)=14  ---(perimeter)

l+b=14     -----1

l*b=25   -----(area)       ---2

b=14-l

l*b=25

l*(14-l)=25

14l - l^2 = 25

l^2 - 14l + 25=0

Determinant= b^2 - 4ac

                     = 14^2 - 4*1*25

                     = 196-100

                      =96

Since, Determinant is greater than 0, it is possible to make a rectangle of perimeter 14cm and area 25cm^2.

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