Math, asked by ducklings345, 8 months ago

Can you factorize x^3 + 5x^2 +7x + 3

Answers

Answered by Anonymous
3

Answer:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

(((x3) - 5x2) + 7x) - 3

STEP

2

:

Checking for a perfect cube

2.1 x3-5x2+7x-3 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-5x2+7x-3

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 7x-3

Group 2: x3-5x2

Pull out from each group separately :

Group 1: (7x-3) • (1)

Group 2: (x-5) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

2.3 Find roots (zeroes) of : F(x) = x3-5x2+7x-3

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is -3.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,3

Answered by drishtidarshandudhe
0

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((x3) -  5x2) +  7x) -  3

STEP

2

:

Checking for a perfect cube

2.1    x3-5x2+7x-3  is not a perfect cube

Trying to factor by pulling out :

2.2      Factoring:  x3-5x2+7x-3  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  7x-3  

Group 2:  x3-5x2  

Pull out from each group separately :

Group 1:   (7x-3) • (1)

Group 2:   (x-5) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

2.3    Find roots (zeroes) of :       F(x) = x3-5x2+7x-3

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  -3.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,3

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -16.00      

     -3       1        -3.00        -96.00      

     1       1        1.00        0.00      x-1  

     3       1        3.00        0.00      x-3  

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

  x3-5x2+7x-3  

can be divided by 2 different polynomials,including by  x-3  

Polynomial Long Division :

2.4    Polynomial Long Division

Dividing :  x3-5x2+7x-3  

                             ("Dividend")

By         :    x-3    ("Divisor")

dividend     x3  -  5x2  +  7x  -  3  

- divisor  * x2     x3  -  3x2          

remainder      -  2x2  +  7x  -  3  

- divisor  * -2x1      -  2x2  +  6x      

remainder             x  -  3  

- divisor  * x0             x  -  3  

remainder                0

Quotient :  x2-2x+1  Remainder:  0

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