Can you help me with this?
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1 ((8*8)+(8*8)*8)-(8+8+8) = 1000
here we r using 8 eight's to get 1000
2 1000=(2222-222)/2
here we r using 8 eight's to get 1000
2 1000=(2222-222)/2
ThePhoenix:
Thanks a lot
Answered by
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Hello friend,
Good logic question.
Let's answer first one
(1)1000=_______(eight 8's)
We have to write 1000 with eight 8's
8,8,8,8 8,8,8,8
1000=888+88+8+8+8
Count the no. of 8's
There are eight 8's.
Add :-888+88+8+8+8=1000
•1000=888+88+8+8+8
•1000=8888/8.888
•1000=[(8*8)+(8*8)]*8-(8+8+8)
•1000=(8888-888)/8
(2)1000=_______(eight 2's)
We have to write 1000 with eight 2's
2,2,2,2,2,2,2,2
1000=(2222-222)/2
Count the no. of 2's
there are eight 2's
hope this helps you
Good logic question.
Let's answer first one
(1)1000=_______(eight 8's)
We have to write 1000 with eight 8's
8,8,8,8 8,8,8,8
1000=888+88+8+8+8
Count the no. of 8's
There are eight 8's.
Add :-888+88+8+8+8=1000
•1000=888+88+8+8+8
•1000=8888/8.888
•1000=[(8*8)+(8*8)]*8-(8+8+8)
•1000=(8888-888)/8
(2)1000=_______(eight 2's)
We have to write 1000 with eight 2's
2,2,2,2,2,2,2,2
1000=(2222-222)/2
Count the no. of 2's
there are eight 2's
hope this helps you
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