Question

Can you please solve this.

Answer 1

(a) work done=force × displacement
=100×5
=500 Nm
(b) Increase in potential energy=U2-U1
=mgh-0 (given, mg=100 nd h=3m)
=100×3
=300 Nm

(c) difference b/w work done nd potential energy=500-300=200 Nm


I HOPE IT WILL HELP YOU