Question

can you please solve this two question it's urgently plzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Answer 1

Answer :

$1. \: 8x {}^{3} + 27 {y}^{3} \\ \\ write \: the \: number \: in \: exponential \: form \: \\ with \: exponent \: 3 \\ \\ {2}^{3} {x}^{3} + {3}^{3} {y}^{3} \\ \\ calculate \: the \: product \\ \\ {(2x)}^{3} + (3y) {}^{3} \\ \\ factor \: the \: expression by \: using \\ {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) \\ \\ ( 2x + 3y)(( {2x})^{2} - 2x \times 3y + ( {3y})^{2} ) \\ \\ (2x + 3y)( {4x}^{2} - 6xy + {9y}^{2} )$

$given \: \\ 2x + 3y = 14 \\ xy = 8 \\ \\ put \: these \: values \: \\ in \: the \: expression \: we \: get\\ \\ (14)( {4x}^{2} - 6(8) + {9y}^{2} ) \\ \\ {56x}^{2} - 672 + {126y}^{2}$

$2. \: {27a}^{3} + 8 {b}^{3} \\ \\ {3}^{3} {a}^{3 } + {2}^{3} {b}^{3} \\ \\ ( {3a)}^{3} + ( {2b)}^{3} \\ \\ (3a + 2b)(( {3a)}^{2} - 3a \times 2b + ( {2b)}^{2} ) \\ \\ (3a + 2b)(9 {a}^{2} - 6ab + 4 {b}^{2} )$

$(3a + 2b) = 6 \\ \\ ab = 2 \\ \\ put \: the \: values \: in \: the \: expression \\ \\ (6)( {9a}^{2} - 6(2) + {4b}^{2} ) \\ \\ {54a}^{2} - 72 + 24 {b}^{2}$

HOPE IT WOULD HELP YOU

Answer 2

Heyyyy mate

here is your answer

hope it help you