Question

case study question in a safety car parking charges are rupees 30 for first two hours and rupees 10 hours for substitute hours
Answer the following questions:-
1. Taking total parking time to be X hours and total charges in rupees why write a linear equation-
a) 10x+y-10=0. b) 10x-y+10=0
c) 8x+y-10=0. d) 8x-y+10=6
2. If y=20,x=?
3. If x=2,y=?
4. If charges of a car in parking lot is rupees 50 for first three hours then write linear equation for it​

Answer 1

Answer:

Parking charges for first 2 hrs = Rs 30Parking charges for subsequent hrs = Rs 10Total park time = x hoursTotal charges = Rs yy = 30 + 10(x- 2)y = 30 + 10x - 2010x - y = -10

Step-by-step explanation:

Mark as brainliest

And follow