cave lenses of focal length 15 cm find distance of object from the lens be placed so that an image at 10 cm from the lens and magnification produced by the lens
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f= -15 cm (concave)
v=10cm
u=?
1/f=1/v+1/u
1/-15-1/10=1/u
-2+-3/30=1/u
u=-6cm ans.
m-v/u
m=-10/-6
m=5/3ans
v=10cm
u=?
1/f=1/v+1/u
1/-15-1/10=1/u
-2+-3/30=1/u
u=-6cm ans.
m-v/u
m=-10/-6
m=5/3ans
Dufferboy:
How can you take v = +vr
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