Question

Ce-58
is a member of
A) s-block elements B) p-block elements C) d-block elements D) f-block elements

Answer 1

d)f-block elements (58 comes in lanthanide series which id f block element )

Answer 2

Answer: Correct option is D.

Explanation: We are given an element Cerium having atomic number 58.

Electronic configuration of Cerium = $[Xe]6s^25d^14f^1$

As the last electron goes to the f-orbital, hence the valence shell is f-shell.

Therefore, the element is a member of f-block of the periodic table. This element is the second element of the lanthanide series.