Physics, asked by aryansah3478, 1 year ago

Centre of gravity of a semicircular lamina is at a distance of

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Answered by Anonymous

The Centre of gravity of Semi-circular lamina will be 2r/pie.
Note:- pie = 3.1415... = 22/7 (approx.)

This can be proved by integration method, by considering infinitesimal element dm.

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