Question

Ch algebric expressions plz... Tell​

Answer 1

Answer:

-985

Step-by-step explanation:

$(7x+11y)(7x-11y) + 55\\\\= (7x)^2 - (11y)^2 + 55\\\\= 49x^2 - 121y^2 + 55\\\\\text{Put x = -1 andd y = 3}\\\\49(-1)^2 - 121(3)^2 + 55\\\\= 49(1) - 121(9) + 55\\\\= 49 - 1089 + 55\\\\= 104 - 1089\\\\= \bold{-985}$

Answer 2

Solution :

$(7x\: + \: 11y)(7x\:-\;11y) \: + \:55$

Now

( a + b )( a - b ) = a² - b²

= (7x)² - (11y)² + 55

x = -1 & y = 3

Put the value of x & y

= [7(-1)]² - [11(3)]² + 55

= [49(1)] - [121(9)] + 55

= [49] - [1089] + 55

= [49] - [1034]

= -985

Answer

$\boxed{(7x\: + \: 11y)(7x\:-\;11y) \: + \:55 \: = \: 985}$