(CH₃)₂C = CHCH₃ + NOBr → product. The structure
of the product is
(a) (CH₃)₂ C(NO) – CH(Br)CH₃
(b) (CH₃)₂ C(Br) – CH(NO)CH₃
(c) (CH₃)₂ CH – C(NO)(Br)CH₃
H
|
(d) H₃C – C – CH – CH₃
| |
NO CH₃
Answers
Answered by
1
Answer:
option b was correct
hope I'm correct
NOBr divides as NO+ and Br-
negative charged bromine goes towards bulky group
positively charged NO moves towards less bulkier group
Similar questions