Question

Challenge to all,Maths question,:-Father's age is 3 times the sum of ages of his two children. After 5 years his age will be the twice the sum of age of two children. Find the age of father​

Answer 1

Answer:

45 years

Step-by-step explanation:

Let the sum of ages of two children be x and father's age be y

1. Presently ,

y=3x

2. After 5 years,

Age of father = y+5

Sum of ages of two children = x + 10

Now => (y+5) = 2(x +10)

Put y = 3x

(3x+5) = 2x + 20

x = 15

So, y = 45yrs.

Answer 2

$\mathcal{\underline{QUESTION-}}$

Father's age is 3 times the sum of ages of his two children. After 5 years his age will be the twice the sum of age of two children. Find the age of father.

$\mathcal{\underline{ANSWER-}}$

Age of father will be 45 years.

$\mathcal{\underline{STEP-BY-STEP \ EXPLANATION-}}$

Let the age of father be $\sf{x}$ years and sum of the ages of two children be $\sf{y}$ years.

After 5 years,

Father's age = $\sf{(x+5)}$ years

Sum of ages of his children = $\sf{(y+10)}$ years

According to question,

$\sf{x=3y}$ ----------(1)

$\sf{x+5=2(y+10)}$

$\sf{x-2y=15}$ ----------(2)

From (1) and (2),

$\sf{3y-2y=15}$

$\sf{y=15}$

Substituting value of $\sf{y}$ in (1),

$\sf{x=3y=3\times 15=45}$