find the total surface area of hollow cylinder open at both ends if its length is 28 CM external radius is 7 cm and thickness is 1 cm
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Answer:
Step-by-step explanation:
Given for the hollow cylinder with open at both ends, length is h=12 cm, external diameter is 8 cm and the thickness is 2 cm.
Then external radius is r1
=4 cm and internal radius isr2
=4−2=2 cm.
Now the total surface area of the hollow cylinder will be,
=2×π×(r1 −r2 )×h
=2×π×(4−2)×12
=48π cm2
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