Chandigarh Rto prove that root 5 is irrational number
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❄here is ur answer❄
To prove → √5 is irrational
⏩Proof ⤵⤵
✔let √5 be rational number.✔
so,
↪√5=p/q,where p and q are co-prime numbers.
→squaring on both sides , we get ←
↪5=p²/q²
↪5q²=p²...........( 1 )
▪this indicates
p is multiple of 5▪
✔let p=5t for some integer "t"✔
replace value of "t" in equation.. ( 1 )
↪5q²=(5t)²
↪5q²=25t²
↪q²=5t².......(2)
▪this indicates
q is multiple of 5▪
since,p and q has 5 as common factor.this contradict the fact that p and q are co-prime.
hence,√5 is not a rational number.
✏√5 is irrational number.
((((((((hence,
proved))))))))
hope it helps______with reGarDs ========== SnehaG☑
❄here is ur answer❄
To prove → √5 is irrational
⏩Proof ⤵⤵
✔let √5 be rational number.✔
so,
↪√5=p/q,where p and q are co-prime numbers.
→squaring on both sides , we get ←
↪5=p²/q²
↪5q²=p²...........( 1 )
▪this indicates
p is multiple of 5▪
✔let p=5t for some integer "t"✔
replace value of "t" in equation.. ( 1 )
↪5q²=(5t)²
↪5q²=25t²
↪q²=5t².......(2)
▪this indicates
q is multiple of 5▪
since,p and q has 5 as common factor.this contradict the fact that p and q are co-prime.
hence,√5 is not a rational number.
✏√5 is irrational number.
((((((((hence,
proved))))))))
hope it helps______with reGarDs ========== SnehaG☑
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