Question

change in volume when 100 ml PH3 decomposed to solid p &H2gas.

Answer 1

Reaction is 2PH3=2 P+3H2 3/2*100=150 thus change in volume =150-100=50ml

Answer 2

Hey dear,

● Answer -
∆V = +50 ml

● Explanation -
Decomposition of phosphine on heating gives solid phosphorus and hydrogen gas.
Reaction is expressed as -
2PH3(g) ---> 2P(s) + 3H2(g)

Here, 2 L of PH3 gas => 3 L of H2 gas
Thus, 100 ml of PH2 => 100×3/2=150 ml of H2.

Change in volume is -
∆V = 150 - 100
∆V = 50 ml

Therefore, change in volume is +50 ml.

Hope this helps you...