Question

Check the roots of quadratic equation X square + bx + c equal to zero B square minus 4 AC is greater than 0

Answer 1

Answer:

F(x)=X^2+bx+c=0

.: D=b^2-4ac

As,

D=b^2-4ac>0

.: x=(-b)+(√b^2-4ac) ÷ 2a

& x=(-b)-(√b^2-4ac) ÷ 2a

Answer 2

quadratic equation has two distinct real roots

Step-by-step explanation:

given quadratic equation

$x^2+bx+c=0$

here , a = 1

if the value of $b^2-4ac > 0$

that means it has two distinct real roots

therefore ,

roots are

$x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

then for this equation roots are given by

$x= \frac{-b+ \sqrt{b^2-4c}}{2}, x= \frac{-b- \sqrt{b^2-4c}}{2}$

#Learn more :

For the equation 3 x square + bx + 3 is equal to zero is greater than zero is one of the root is square of the other is equal to

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