Check whether 140 is a term of the Ap -7 -4 -1 ,2
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Answered by
1
Answer:
a=-7
d=3
an=140
an=a+(n-1)d
140=-7+(n-1)3
140=-7+3n-3
140=-10+3n
150=3n
n=50 hence 140 is there in AP as 50th term
Answered by
1
an=140
a=-7
d=-4-(-7)
=3
an=a+(n-1) d
140=-7+(n-1) 3
140+7=(n-1) 3
147=(n-1) 3
147/3=(n-1)
49=(n-1)
49+1=n
50=n
=> 140 is the 50th term of the given A. P.
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