check whether bracket X - 2 bracket is a factor of x cube + 2 X square + 3 x minus 6
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Put x=2 the equation.....my ans is no
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0
let
p(x)=x³+2x²+3x-6,
for remainder
x-2=0,
x=2,
if
(x-2) is a factor of p(x) then
remainder mean p(2) should be zero,
hence
p(2)=2³+2(2)²+3(2)-6,
=8+2×4+6-6,
=8+8,
=16,
since
p(2) not equal to zero
then
(x-2) is not a factor of p(x)
p(x)=x³+2x²+3x-6,
for remainder
x-2=0,
x=2,
if
(x-2) is a factor of p(x) then
remainder mean p(2) should be zero,
hence
p(2)=2³+2(2)²+3(2)-6,
=8+2×4+6-6,
=8+8,
=16,
since
p(2) not equal to zero
then
(x-2) is not a factor of p(x)
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