Question

check whether it is possible to draw a triangle whose sides are given as follows
i) 3cm,6cm,8 cm
ii) 2cm,3cm,5cm
iii) 10cm,15cm,5cm
iv) 5.5cm,2.2cm,6.4cm
v) 7cm,8cm,15cm
vi)12cm,8cm,12cm​

Answer 1

Answer:

this will be done by the property : sum of two sides of a triangle should be more than the third side.

(I) 3cm,6cm,8cm

=(3+6)=8

=9=8

LHS>RHS

so triangle is possible.

(ii) 2cm,3cm,5cm

(2+3)=5

5=5

LHS=RHS

triangle is not possible

(iii) 10cm,15cm,5cm

(10+5)=15

15=15

LHS=RHS

so triangle is not possible

(iv) 5.5cm,2.2cm,6.4cm

(5.5+2.2)=6.4

7.7=6.4

LHS>RHS

so triangle is possible

(v) 7cm,8cm,15cm

(7+8)=15

15=15

LHS=RHS

so triangle is not possible

(vi) 12cm,8cm,12cm

(12+8)=12

20=12

LHS>RHS

so triangle is possible

Step-by-step explanation:

LHS is left hand side

RHS is right hand side

write the property in each part that I have written in the starting.

in triangles it's a property that is the sum of two sides should be greater or more than the third side.

hope you understood :)

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Answer 2

Answer:

8(3+6)

8( 9 Yes

ii) 5(3+2)

5( 5 No

iii) 5(15+10)

5( 25 no

iv) 6•4(5•5+2•2