Question

check whether minus 140 is a term of the AP: 11,8,5,2

Answer 1

SOLUTION :
Given : first term (a) = 11 , common difference (d) = 8 - 11 = -3

Let -140 be the nth term
an = a + (n - 1) d

-140 = a+(n-1)d
-140 = 11+(n-1) (-3)
-140 = 11 -3n +3
-140 = 14 - 3n
3n = 140 +14
3n=154
3n= 154
n = 154/3
n = 51.333…..

But n should be an integer
Hence -140 is not the term of the given AP

HOPE THIS ANSWER WILL HELP YOU...

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

Let −150 is the nth of AP 11,8,5,2...     

which means that  an'=−150

Here, First term = a = 11

Common difference = d = 8 - 11 = -3

Using formula an'=a+(n−1)d,  

to find nth term of arithmetic progression, we get

−150=11+(n−1)(−3)

⇒−150=11−3n+3

⇒3n=164

⇒n=164/3

But, n cannot be in fraction. Therefore, our supposition is wrong. −150 cannot be term in AP.

I hope, this will help you.

Thank you______❤

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