check whether X + 1 is a factor of the polynomial x cube + x square + X + 1
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Answered by
41
Hey user !!
Here is your answer !!
_______________________________________________⭐
↪To check that (x + 1) is the factor we will put value of x in the given polynomial .
↪Hence ,
↪x + 1 = 0
↪x = -1
↪p ( x ) = x ^3 + x ^2 + x + 1
↪( -1 )^3 + ( -1 )^2 + ( -1 ) + 1 = 0
↪- 1 + 1 - 1 + 1 = 0
↪0 = 0
↪Hence zero is the required answer
↪( x + 1 ) is the factor of given polynomial.
Hope it is satisfactory :-)
_______________________________________________⭐
Here is your answer !!
_______________________________________________⭐
↪To check that (x + 1) is the factor we will put value of x in the given polynomial .
↪Hence ,
↪x + 1 = 0
↪x = -1
↪p ( x ) = x ^3 + x ^2 + x + 1
↪( -1 )^3 + ( -1 )^2 + ( -1 ) + 1 = 0
↪- 1 + 1 - 1 + 1 = 0
↪0 = 0
↪Hence zero is the required answer
↪( x + 1 ) is the factor of given polynomial.
Hope it is satisfactory :-)
_______________________________________________⭐
Answered by
21
Yeah sure for your help
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®®®®®®®®®®®
✍✍
❤ For check the factor of polynomial we simply put the given value in a place of x or any variable
❤ If your answer is equal to zero both sides then we can say it satisfies
❤ That means x+1 is a factor of p(x) = x^3 +x^2 +x+ 1
❤ In this question we put -1 in the place of x
❤ Refer to this attachment with my answer
®®®®®®®®®®®
✍✍
❣ Hope you satisfied with my answer ❣
Be Brainly
Be Proud
Together we go far
❤ Warm Regards ❤
@ Brainlestuser
****************
®®®®®®®®®®®
✍✍
❤ For check the factor of polynomial we simply put the given value in a place of x or any variable
❤ If your answer is equal to zero both sides then we can say it satisfies
❤ That means x+1 is a factor of p(x) = x^3 +x^2 +x+ 1
❤ In this question we put -1 in the place of x
❤ Refer to this attachment with my answer
®®®®®®®®®®®
✍✍
❣ Hope you satisfied with my answer ❣
Be Brainly
Be Proud
Together we go far
❤ Warm Regards ❤
@ Brainlestuser
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