Math, asked by Mayank784, 1 year ago

check whether (x+1) is a factor of x³-x²-(2+√2)x+√2
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Answers

Answered by AayushGautam
21
No,(x+1) is not the factor of
 {x}^{3}  -  {x}^{2}  - ( 2 +  \sqrt{2})x +  \sqrt{2}
, because:-
let p(x) be x+1
so x= -1
let g(x) be our polynomial
we use remainder theorem
g(x)=
 {3}^{3} -  {x}^{2}   - (2 +  \sqrt{2} )x +  \sqrt{2}
g(-1)=
 - 1 - 1 + 2 +  \sqrt{2}  +  \sqrt{2}
 - 2 + 2 +  \sqrt{2}
2 \sqrt{2}
hence ,the remainder is not zero so p(x) is not the factor of g(x).
Answered by suprioghosh00
0

Step-by-step explanation:

x

3

−x

2

−(2+

2

)x+

2

, because:-

let p(x) be x+1

so x= -1

let g(x) be our polynomial

we use remainder theorem

g(x)=

{3}^{3} - {x}^{2} - (2 + \sqrt{2} )x + \sqrt{2}3

3

−x

2

−(2+

2

)x+

2

g(-1)=

- 1 - 1 + 2 + \sqrt{2} + \sqrt{2}−1−1+2+

2

+

2

- 2 + 2 + \sqrt{2}−2+2+

2

2 \sqrt{2}2

2

hence ,the remainder is not zero so p(x) is not the factor of g(x).

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